Question

Write the equation of a line in point-slope form that has a slope of -1 and passes through the point (-2, 5).

Answer 1

$\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 5}})\quad \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \begin{array}{llll} \textit{plug in the values for } \begin{cases} y_1=5\\ x_1=-2\\ m=-1 \end{cases}\\ \textit{and solve for "y"} \end{array}\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form}$

Answer 2

*Hint: The point-slope form of an equation. is written as (y - y1) = m (x - x1) and y1 and x1 would represent the ordered paired you plug in.

Therefore, you just plug in the slope and ordered pair to get the equation.

(y - 5) = -1 (x + 2)