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A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following morning she finds four pennies. Apparently, while she sleeps each penny turns into two magic pennies.The total number of pennies seen under the pillow each day is the grand total; that is, the pennies from each of the previous days are not being stored away until more pennies magically appear. How many days would elapse before she has a total of more than 90 trillion?

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Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

[tex]1,2,4,8,16,32,.....[/tex]

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

[tex]S_n=\dfrac{a(r^n-1)}{r-1}[/tex]

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

[tex]\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}[/tex]

[tex]\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}[/tex]

[tex]\Rightarrow 90\times 10^{12}\le 2^n-1[/tex]

[tex]\Rightarrow 2^n\ge 90\times 10^{12}+1[/tex]

[tex]\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)[/tex]

[tex]\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)[/tex]

[tex]\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}[/tex]

[tex]\Rightarrow n \ge 46.4[/tex]

[tex]\Rightarrow n\approx 47[/tex]


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