What is the slope-intercept form of the equation of the line that passes through the points (−3, 2) and (1, 5) ?

a. y= 3/4x - 9/2
b. y=3/4x - 7/4
c. y=3/4x + 7/2
d. y=3/4x +17/4

Respuesta :

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -3}}\quad ,&{{ 2}})\quad % (c,d) &({{ 1}}\quad ,&{{ 5}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-2}{1-(-3)}\implies \cfrac{5-2}{1+3}[/tex]

[tex]\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=\cfrac{3}{4}(x-(-3))\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-2=\cfrac{3}{4}(x+3)\implies y-2=\cfrac{3}{4}x+\cfrac{9}{4}\implies y=\cfrac{3}{4}x+\cfrac{9}{4}+2 \\\\\\ y=\cfrac{3}{4}x+\cfrac{17}{4}[/tex]
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