Question

A ball starts from rest. It rolls down a ramp and reaches the ground after 4 seconds. Its final velocity when it reaches the ground is 7.0 meters/second. The initial velocity of the ball is meters/second, and its acceleration is meters/second2. NextReset

Answer 1

If it starts at rest the initial velocity is 0.
For an acceleration, a, and time, t, the velocity is v=at. Since at t=4, v=7, then a=7/4=1.75m/s^2

Answer 2

The initial velocity of the ball is zero while the acceleration of the ball $\bold {1.75\ m/s^2}$.

Acceleration:

It is defined as rate of change in velocity, either speed or direction of the object.

$\bold {a = \dfrac vt}$

Where,

a - acceleration

v - velocity = 7 m/s

t - time = 4 s

Thus,

$\bold { a=\dfrac 74}\\\\\bold {a =1.75\ m/s^2}$

Since, the ball starts at rest. Hence, the initial velocity is 0.

Therefore, the initial velocity of the ball is zero while the acceleration of the ball $\bold {1.75\ m/s^2}$.

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