Answer:
[tex]\dfrac{5x^2-3x+8}{2x+1}[/tex]
Step-by-step explanation:
The denominators are the same, so the numerators can be added in the usual way.
... = ((5x^2 +6) -(3x -2))/(2x +1)
... = (5x^2 +6 -3x +2)/(2x +1)
... = (5x^2 -3x +8)/(2x +1)
The numerator and denominator have no common factors, so this cannot be reduced further.
