Answer:
$6062
Step-by-step explanation:
The formula we are given is
[tex]c=120\sqrt[3]{n^2}+1300[/tex]
We will replace n with 250:
[tex]c=120\sqrt[3]{250^2}+1300\\ \\=120\sqrt[3]{62500} +1300\\\\=120(39.685)+1300\\\\=4762.20+1300\\\\=6062.20 \approx 6062[/tex]