Question

The density of 95% by mass of sulphuric acid is 1.84 g/mL . Calculate the molarity

Answer 1

w=0.95 (95%)
p=1.84 g/mL=1840 g/L
M(H₂SO₄)=98.08 g/mol

n(H₂SO₄)=m(H₂SO₄)/M(H₂SO₄)
m(H₂SO₄)=wpV

C=n(H₂SO₄)/V

C=wpV/{M(H₂SO₄)V}=wp/M(H₂SO₄)

C=0.95*1840g/L/(98.08g/mol)=17.82 mol/L

17.82 M H₂SO₄

Answer 2

the answer is 17.82 M H₂SO₄