Respuesta :
Answer: The correct option is (B) x = 4 and x = -4.
Step-by-step explanation: We are given to find the solutions to the following quadratic equation :
[tex]x^2-16=0~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
Since the coefficient of x is zero in the given equation, so we will be using the method of square root to solve the equation.
From equation (i), we have
[tex]x^2-16=0\\\\\Rightarrow x^2=16\\\\\Rightarrow x=\pm\sqrt{16}~~~~~~~\textup{[taking square root on both sides]}\\\\\Rightarrow x=\pm4\\\\\Rightarrow x=4,~-4.[/tex]
Thus, the required solution is x = 4 and x = -4.
Option (B) is correct.
The correct statement is that the solution of this equation x² – 16 = 0, is 4 and -4.
What is a quadratic equation?
It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation. The general form of the quadratic equation is ax² + bx + c = 0
Given
The quadratic equation x² – 16 = 0
To find
The root of the quadratic equtaion?
How do find the solutions to the quadratic equation?
The quadratic equation x² – 16 = 0
We know the formula,
a² - b² = ( a - b ) ( a + b )
Then
x² – 4² = 0
(x - 4)(x + 4) = 0
x = 4 and -4
Thus, the solution of this equation x² – 16 = 0, is 4 and -4.
More about the quadratic equation link is given below.
https://brainly.com/question/2263981
