Question

There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. Barbara selects 2 ice creams at random without replacement. What is the probability that she selects 2 chocolate ice creams?

Answer 1

3 strawberry, 4 chocolate, 7 vanilla...total of 14

probability of 1st pick being chocolate = 4/14 reduces to 2/7
without replacing
probability of 2nd pick being chocolate = 3/13

probability of both = 2/7 * 3/13 = 6/91 <==