Question

Suppose A and B are independent events. If P(A)=0.2 and P(B)=0.6, what is P(A^B)?

a 0.2
b 0.12
c 0.08
d 0.6

Answer 1

OK so you want the probabilty of A and B occurring.  Independet event probabilities are multiplied so its 0.2 * 0.6 = 0.12

b

Answer 2

Answer: $P(A\cap B)=0.12$

Step-by-step explanation:

We know that if two events M and N are independent, then the probability of the intersection of the two events is given by :-

$P(M\cap N)=P(M)\times P(N)$

Given: The events A and B are independent .

Therefore, $P(A\cap B)=P(A)\times P(B)$

If P(A)=0.2 and P(B)=0.6

Then,

$P(A\cap B)=0.2\times 0.6\\\\\Rightarrow P(A\cap B)=0.12$