Question

How many moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen? Use this balanced equation for the Haber process: N2 (g) + 3 H2 (g) → 2 NH3

Answer 1

3 mol H₂ → 2 mol NH₃

5 mol H₂ → x mol NH₃

x=2*5.0/3=3.3

n(NH₃)=3.3 mol

Answer 2

When 5.0 moles of hydrogen react with excess nitrogen 3.33 moles of Ammonia is produced.

What is Haber's Process ?

The process of formation of ammonia (colourless gas) , from Nitrogen and Hydrogen at 200 to 400 atmospheres and at temperatures ranging from 400° to 650° C.

The equation is given as

N₂ (g) + 3 H₂ (g) → 2 NH₃

Now it can be understood that mole ratio of Nitrogen : Hydrogen : Ammonia  = 1 : 3 : 2

Hydrogen moles present = 5 moles

Moles of Nitrogen >5/3 moles  (excess nitrogen)

Ammonia formed is = ?

Therefore if 3 moles of Hydrogen makes 2 moles of Ammonia

5 moles of Hydrogen will make 5*2/3 = 3.33 moles of Ammonia

when 5.0 moles of hydrogen react with excess nitrogen 3.33 moles of Ammonia is produced.

To know more about Haber's Process

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