Respuesta :
u didnt post a graph...so let me try and explain this line...
y = -3/5x + 1
slope = -3/5....negative slope means ur line is going down (decreasing)
ur y int is 1....that means the line crosses the y axis at (0,1)
ur x int can be found by subbing in 0 for y and solving for x...
0 = -3/5x + 1
3/5x = 1
x = 1 * 5/3
x = 5/3....so ur x int is (5/3,0)....5/3 = 1 2/3 for graphing purposes
so start at (0,1).....and since ur slope is -3/5, go down 3 spaces and to the right 5 spaces....ur line will cross the x axis at (5/3,0)
y = -3/5x + 1
slope = -3/5....negative slope means ur line is going down (decreasing)
ur y int is 1....that means the line crosses the y axis at (0,1)
ur x int can be found by subbing in 0 for y and solving for x...
0 = -3/5x + 1
3/5x = 1
x = 1 * 5/3
x = 5/3....so ur x int is (5/3,0)....5/3 = 1 2/3 for graphing purposes
so start at (0,1).....and since ur slope is -3/5, go down 3 spaces and to the right 5 spaces....ur line will cross the x axis at (5/3,0)
Answer with Step-by-step explanation:
We are given that a function
[tex]y=-\frac{3}{5}x+1[/tex]
We have to graph the given function .
Substitute x=0 then we get
[tex]y=-\frac{3}{5}\times 0+1=1[/tex]
The given equation cut the y- axis at y=1
Now, substitute y=0 then, we get
[tex]0=-\frac{3}{5}x+1[/tex]
[tex]\frac{3}{5}x=1[/tex]
[tex]x=\frac{5}{3}=1.667[/tex]
Hence, the equation cut the x- axis at x=1.667
Therefore, the equation passing through the point (1.667,0) and (0,1).
Now, mark point (1.667,0) and (0,1) on the graph paper and then meet these points.
