A jumbo jet must reach a speed of 360 km/h (= 225 mi/h) on the runway for takeoff. assuming a constant acceleration and a runway 1.50 km long, what minimum acceleration from rest is required?

Respuesta :

We just consider the moves of the jumbo jet, not it's causes (we solve it kinematically)

It has a constant acceleration, so then we may use this equation to solve our problem: a = Vf^2 - Vo^2 / 2∆x

Vf (The max velocity that allowed) = 360 Km/h
Vo = 0 (At rest)
∆x = 1.5 Km

then..

a = (360)^2 / (2)(1.5) = 43200 Km/h^2

Convert those numbers to m/sec^2 you will surprised by the results=))
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