Question

Find the probability using the standard normal distribution. p(–2.14 < z < 0.95)

a. 0.8127

b. 0.1873

c. 0.0681

d. 0.1170

Answer 1

From standard normal distribution tables, obtain
p(z=0.95) = 0.8289
p(z = -2.14) = 0.0162

Therefore
p(-2.14 < z < 0.95) = 0.8289 - 0.0162 = 0.8127

Answer: a. 0.8127