Question

The perimeter of a rectangle is 200 yards. what are the dimensions of the rectangle if the length is 80 yards more than the? width?

Answer 1

P = 2(L + W)
P = 200
L = W + 80

200 = 2(W + 80 + W)
200 = 2(2W + 80)
200 = 4W + 160
200 - 160 = 4W
40 = 4W
40/4 = W
10 = W.........the width is 10 yds