Question

A target has a bull’s-eye with a diameter of 2 inches. the outer ring is 1 inch wide. what is the area of the outer ring?

Answer 1

The diameter of the outer ring will be 4 inches since it extends one inch beyond the bull's eye from either side. See the attached image for clarification.

The area of the outer ring can be expressed as:
$Area_{outerring} = Area_{outercircle} - Area_{bullseye}$
This is because we need to take into account of the space taken up by the bullseye. 

Now we set up our equation:
$Area_{outerring} = \pi r^{2}_{outercircle} - \pi r^{2}_{bullseye}$

Now plug and solve:
$Area_{outerring} = \pi 2^{2} - \pi 1^{2}$
$Area_{outerring} = 4\pi - \pi$
$Area_{outerring} = 9.42477796$