Respuesta :

[tex]sin60^o= \frac{a}{2 \sqrt{2} } \ \ \to \ a=2 \sqrt{2} *sin60^o=2 \sqrt{2}* \frac{ \sqrt{3}}{2}= \sqrt{6} \\ \\ cos60^o = \frac{b}{2 \sqrt{2} } \ \ \to \ b=2 \sqrt{2} *cos60^o=2 \sqrt{2}*0.5= \sqrt{2}[/tex]

Answer: a=√6,  b=√2
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