Question

ABCD is a rectangle. Find the length of each diagonal.
AC=3y/5
BD=3y-4

Answer 1

The diagonals of a rectangle are equal, so

$\frac{3y}{5} = 3y-4$, then multiply both sides by 5
3y = 5(3y - 4) Distribute the 5
3y = 15y - 20 Subtract 15y from both sides
-12y = -20 Divide both sides by -12
y = $\frac{5}{3}$

So, AC = $\frac{3(5/3)}{5} = 1$
and BD = 3(5/3) - 4 = 1

Answer 2

The value of y is 5/3. Then the length of the diagonals of the rectangle will be 1 unit.,

What is a rectangle?

It has four sides and is a polygon. The internal angle adds up to 360 degrees. The opposing sides of a rectangle are parallel and equal, and each angle is 90 degrees. Its diagonals are equally equal, intersecting at the middle.

ABCD is a rectangle.

If the diagonals are AC = 3y/5 and BD = 3y - 4

Then the diagonals of the rectangle are equal, then we have

AC = DB

Put the value then we have

3y/5 = 3y - 4

   3y = 15y - 20

 12y = 20

    y = 5/3

Then the length of the diagonals will be

$\rm AC = \dfrac{3}{5} \times \dfrac{5}{3}\\\\AC = 1\\\\BD = 3\times \dfrac{5}{3}-4\\\\BD = 5- 4\\\\BD = 1$

More about the rectangle link is given below.

https://brainly.com/question/10046743

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