Question

Given any triangle abc labeled as shown, the law of sines states:

Answer 1

D, sin A/a = Sin B/b = Sin C/c

Answer 2

Answer

$\frac{sinA}{a} =\frac{sinB}{b} = \frac{sinC}{c}$

Explanation

The law of sine relates the angles in a triangle with their corresponding length.

The ratio of sine of an angle to its  opposite length is constant for any given triangle.

In the case of the given triangle the law of sine will apply as shown bellow:

$\frac{sinA}{a} =\frac{sinB}{b} = \frac{sinC}{c}$