Question

Which function is a quadratic function?
t(x) = (x – 4)2 + 3
q(x) = (2x + 4)3 + 3
r(x) = (–6x – 4)4 + 3(x + 2)2
s(x) = –(x – 6) + 3(x + 1)

Answer 1

t(x) is the only function up above where the highest degree is a 2, which is what a quadratic function is: a function of degree 2

Answer 2

Answer:

Option (1) is correct.

function t(x) is a quadratic function.

Step-by-step explanation:

Given :  four function t, q, r and s .

We have to choose a function out of given function that is a quadratic function.

A function is said to be a quadratic function which is of the form $y=ax^2+bx+c$ with $a\neq 0$ that is the highest degree of variable must be 2.

Thus, out of given functions on t(x) has the highest degree 2.

$t(x) = (x-4)^2 + 3\\\\\\\text{Using identity} (a-b)^2=a^2+b^2-2ab\\\\\t(x) = x^2+16-8x+3\\\\t(x) = x^2-8x+19$

Thus, Option (1) is correct.

Thus, function t(x) is a quadratic function