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The discriminant of a quadratic equation is the value b^2 – 4ac. What is the value of the discriminant of 0 = –2x^2 + 6x + 13?

Respuesta :

Δ(discriminent) = b²-4ac
Calculate Δ of: -2x² + 6x +13, where:
a= -2
b=6
c=13
THEN Δ = 6² - 4(-2)(13) = 36 -4(-26) = 36 +104 and Δ = 140

Answer:

140

Step-by-step explanation:

i did it on edge

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