Question

What is the standard form of (2-4i)(3+5i)/(3+i)?

Answer 1

$\dfrac{(2-4i)(3+5i)}{3+i}=\\ \dfrac{6+10i-12i+20}{3+i}=\\ \dfrac{26-2i}{3+i}=\\ \dfrac{(26-2i)(3-i)}{9+1}=\\ \dfrac{78-26i-6i-2}{10}=\\ \dfrac{76-32i}{10}=\\ \dfrac{38}{5}-\dfrac{16}{5}i$

Answer 2

Answer:

AKA Letter Choice E on Plato!!