Question

what are the values of a, b, and c in the quadratic equation -2x^2+4x-3=0

Answer 1

Answer:

$a=-2\\b=4\\c=-3$

Step-by-step explanation:

We know that a standard form of equation in quadratic is

$ax^2+bx+c=0$

We are given an equation as

$-2x^2+4x-3=0$

To find a,b and c, it is sufficient to compare the given equation with std form

Comparing $-2x^2+4x-3=0$ with $ax^2+bx+c=0$

equate the coefficients of corresponding terms.

So we have

$a=-2\\b=4\\c=-3$