Question

The vertex form of the equation of a parabola is y=(x-3)^2+36 what is the standard form of the equation

Answer 1

hello :
y = (x-3)²+36
the vertex is : (3 , 36)
y= x²-6x+9+36
y = x² -6x +45... (tandard form)  

Answer 2

Standard form of the equation of a parabola y = $(x-3)^{2}+36$ is $y=x^{2} -6x+45$

What is parabola?

A parabola is a plane curve which is mirror-symmetrical and is approximately U-shaped.

What is vertex form?

The vertex form of a quadratic equation is y = a ( x − h ) 2 + k

What is standard form?

The standard quadratic form is a $x^{2} +bx+c=y$

Given,

Vertex form

y = $(x-3)^{2}+36$

The standard quadratic form is a $x^{2} +bx+c=y$

Then,

$y=x^{2} -6x+9+36\\y=x^{2} -6x+45$

Hence, Standard form of the equation of a parabola y = $(x-3)^{2}+36$ is

$y=x^{2} -6x+45$

Learn more about Parabola, Vertex form and Standard form here

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