Question

the product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring. what is the constant of the quadratic expression in this equation x^2 + x + _________=0

Answer 1

hello : 
 two consecutive integers are : x , x+1
x(x+1) =420 
x² +x - 420 =  
the constant of the quadratic expression in this equation x^2 + x + _____-420____=0

Answer 2

Answer:

The constant of the quadratic expression in this equation x^2+x+_________=0 is:

                         -420

Step-by-step explanation:

Let one of the integer be x , then the other integer will be x+1 ; such that:

              x(x+1)=420-----------(1)

( Since it was given that:

The product of two consecutive integers is 420 )

Hence, on solving the above equation i.e. equation (1) we get:

     $x^2+x=420\\\\\\i.e.\\\\\\x^2+x-420=0\\\\\\i.e.\\\\\\x^2+x+(-420)=0$

                Hence, the constant is:

                           -420