Respuesta :
Answer: The enthalpy of combustion per mole of methane is 801.28 kJ.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of methane = 2.50 g
Molar mass of methane = 16 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of methane}=\frac{2.50g}{16g/mol}\\\\\text{Moles of methane}=0.156mol[/tex]
We are given:
Enthalpy of combustion for given mass = 125 kJ
Using unitary method, we get:
If 0.156 moles of methane has an enthalpy of combustion as 125 kJ.
So, 1 mole of methane has an enthalpy of combustion = [tex]\frac{125kJ}{0.156mol}\times 1mol=801.28kJ[/tex]
Hence, the enthalpy of combustion per mole of methane is 801.28 kJ.
The enthalpy of combustion per mole of methane = 7.8125 kJ/mole
The chemical formula of methane = [tex]CH_4[/tex]
The mass of methane = 2.5 g
The molar mass of [tex]CH_4[/tex] = [tex]12 + (1 \times 4)[/tex]
The molar mass of [tex]CH_4[/tex] =12 + 4
The molar mass of [tex]CH_4[/tex] = 16 g/mol
Enthapy of combustion = 125 kJ
Enthalpy of combustion per mole = [tex]\frac{Enthalpy}{Mole}[/tex]
Enthalpy of combustion per mole = 125/16
Enthalpy of combustion per mole = 7.8125 kJ/mole
Learn more here: https://brainly.com/question/10798851
