Consider triangle ABC with m < C = 65 degrees , b = 5 and c = 6. Which option lists an expression that is equivalent to m < B? a. 6/5sin65 b. 5sin65/6 c. sin^-1(6/5sin65) d. sin^-1(5sin65/6)

Respuesta :

Answer:

[tex]B=sin^{-1}[(5\frac{sin65}{6})][/tex]

Step-by-step explanation:

In a triangle ABC m∠ C = 65°, b = 5 and c = 6.

We have to find m∠ B.

When we apply sine rule in triangle ABC

[tex]\frac{sinB}{b}=\frac{sinC}{c}[/tex]

[tex]\frac{sinB}{5}=\frac{sinC}{c}[/tex]

[tex]sinB=(b)(\frac{sinC}{c})=(5).(\frac{sin65}{6})[/tex]

[tex]B=sin^{-1}[(5\frac{sin65}{6})][/tex]

Option D. is the answer.

Answer:

[tex]d.sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]

Step-by-step explanation:

We are given that a triangle ABC

[tex]m\angle C=65^{\circ}[/tex]

[tex]b=5 units [/tex]

[tex]c=6 units[/tex]

We have to find that option which is equivalent to measure of B.

Sine Law: [tex]\frac{a}{sinA}=\frac{b}{sin B}=\frac{c}{sinC}[/tex]

Using sine law

[tex]\frac{b}{sin B}=\frac{c}{sinC}[/tex]

Substitute the values then, we get

[tex]\frac{5}{sin B}=\frac{6}{sin 65}[/tex]

Cross- multiply then we get

[tex]5 sin65^{\circ}=6 sinB[/tex]

[tex] sin B=\frac{5 sin65^{\circ}}{6}[/tex]

By division property of equality

[tex] B=sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]

Answer:[tex]d.sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]

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