Respuesta :
Answer:
[tex]B=sin^{-1}[(5\frac{sin65}{6})][/tex]
Step-by-step explanation:
In a triangle ABC m∠ C = 65°, b = 5 and c = 6.
We have to find m∠ B.
When we apply sine rule in triangle ABC
[tex]\frac{sinB}{b}=\frac{sinC}{c}[/tex]
[tex]\frac{sinB}{5}=\frac{sinC}{c}[/tex]
[tex]sinB=(b)(\frac{sinC}{c})=(5).(\frac{sin65}{6})[/tex]
[tex]B=sin^{-1}[(5\frac{sin65}{6})][/tex]
Option D. is the answer.
Answer:
[tex]d.sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]
Step-by-step explanation:
We are given that a triangle ABC
[tex]m\angle C=65^{\circ}[/tex]
[tex]b=5 units [/tex]
[tex]c=6 units[/tex]
We have to find that option which is equivalent to measure of B.
Sine Law: [tex]\frac{a}{sinA}=\frac{b}{sin B}=\frac{c}{sinC}[/tex]
Using sine law
[tex]\frac{b}{sin B}=\frac{c}{sinC}[/tex]
Substitute the values then, we get
[tex]\frac{5}{sin B}=\frac{6}{sin 65}[/tex]
Cross- multiply then we get
[tex]5 sin65^{\circ}=6 sinB[/tex]
[tex] sin B=\frac{5 sin65^{\circ}}{6}[/tex]
By division property of equality
[tex] B=sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]
Answer:[tex]d.sin^{-1}(\frac{5 sin65^{\circ}}{6})[/tex]