Respuesta :
Let r = radius of the circle.
The circumference is C = 2πr.
The area is A = πr^2.
Because the circumference is greater than the area, therefore
[tex]2 \pi r\ \textgreater \ \pi r^{2} [/tex]
[tex]1\ \textgreater \ \frac{ \pi r^{2} }{2 \pi r} [/tex]
[tex]1\ \textgreater \ \frac{r}{2} [/tex]
Therefore the radius should satisfy
r < 2
The circumference is C = 2πr.
The area is A = πr^2.
Because the circumference is greater than the area, therefore
[tex]2 \pi r\ \textgreater \ \pi r^{2} [/tex]
[tex]1\ \textgreater \ \frac{ \pi r^{2} }{2 \pi r} [/tex]
[tex]1\ \textgreater \ \frac{r}{2} [/tex]
Therefore the radius should satisfy
r < 2
Answer:
(A) 1/2 (B) 1 (C) 1.5
Step-by-step explanation:
The first three choices will result in a numerical value for the radius that is smaller than the area.
also...
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