Respuesta :

Let's run through the steps

1. x(x+3)+(x+3)-3    ----------------------------    Distribute
2. [tex] x^{2} +3x-3x-9[/tex]   ---------------     Simplify
3. [tex] x^{2} -9[/tex]   -------------------------     Simplify


The product of [tex]\rm (x+3)(x-3)[/tex] is [tex]\rm \bold{ x^2 -9}[/tex]

The product of two algebraic terms is expressed as formulated in equation (1)

Let the first term be [tex]\rm (a+b)[/tex]

Let the second  term be [tex]\rm (a-b)[/tex]

The product of both the terms is given

[tex]\rm (a+b) (a-b ) = a^2 -b^2.........(1)[/tex]

Equation (1) is an algebraic identity

This can be proved in the following way

The product of two terms is given by as formulated in equation (2)

[tex]\rm (x+y)\times (p+q) = px +qx +py +qy......(2)[/tex]

[tex]\rm hence, (a+b) (a-b) = a^2 -ba +ab -b^2 = a^2 -b^2[/tex]

We have to find out the product of (x + 3)(x − 3)

On comparing it with equation (1) we get

a = x

b = 3

from the equation (1) we can get

[tex]\rm (x +3)(x-3) = x^2 -3^2 = x^2 -9[/tex]

So the product of [tex]\rm (x+3)(x-3)[/tex] is [tex]\rm \bold{ x^2 -9}[/tex]  

For more information please refer to the equation

https://brainly.com/question/17212909

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