Respuesta :
Let's run through the steps
1. x(x+3)+(x+3)-3 ---------------------------- Distribute
2. [tex] x^{2} +3x-3x-9[/tex] --------------- Simplify
3. [tex] x^{2} -9[/tex] ------------------------- Simplify
1. x(x+3)+(x+3)-3 ---------------------------- Distribute
2. [tex] x^{2} +3x-3x-9[/tex] --------------- Simplify
3. [tex] x^{2} -9[/tex] ------------------------- Simplify
The product of [tex]\rm (x+3)(x-3)[/tex] is [tex]\rm \bold{ x^2 -9}[/tex]
The product of two algebraic terms is expressed as formulated in equation (1)
Let the first term be [tex]\rm (a+b)[/tex]
Let the second term be [tex]\rm (a-b)[/tex]
The product of both the terms is given
[tex]\rm (a+b) (a-b ) = a^2 -b^2.........(1)[/tex]
Equation (1) is an algebraic identity
This can be proved in the following way
The product of two terms is given by as formulated in equation (2)
[tex]\rm (x+y)\times (p+q) = px +qx +py +qy......(2)[/tex]
[tex]\rm hence, (a+b) (a-b) = a^2 -ba +ab -b^2 = a^2 -b^2[/tex]
We have to find out the product of (x + 3)(x − 3)
On comparing it with equation (1) we get
a = x
b = 3
from the equation (1) we can get
[tex]\rm (x +3)(x-3) = x^2 -3^2 = x^2 -9[/tex]
So the product of [tex]\rm (x+3)(x-3)[/tex] is [tex]\rm \bold{ x^2 -9}[/tex]
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