[tex]\bf 2\left(\frac{1}{2} \right)+3+\cfrac{1}{7}\implies \cfrac{2}{2}+3+\cfrac{1}{7}\implies 1+3+\cfrac{1}{7}\impliedby \textit{LCD of 7}
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\cfrac{7\cdot 1j+7\cdot 3+1\cdot 1}{7}\implies \cfrac{7+21+1}{7}\implies \cfrac{29}{7}\implies 4\frac{1}{7}[/tex]
