Respuesta :
Answer;
62,500 Joules
Explanation;
- Efficiency is a measure of how much work or energy is conserved in a process. It can be stated as the percentage of the output work divided by the input work minus the work lost from to friction and heat.
Efficiency = (output work/ input work) × 100%
80 % = 50,000 / input work × 100%
0.8 = 50,000 /input work
Input work = 50,000/0.8
= 62500 Joules
Thus; the work input is 62,500 joules.
The input work for the machine is 62500 Joules.
What is Efficiency?
The efficiency of an object is defined as a dimensionless number that measures the effectiveness of the object in transforming the power input to the device to power output.
The mathematical expression of the efficiency is given below.
[tex]E = \dfrac {O}{I} \times 100[/tex]
Where E is the efficiency, O is the output work and I is the input work.
Given that the efficiency of the machine is 80% and output work is 50,000 J. The input work can be calculated as given below.
[tex]80 = \dfrac { 50000}{I }\times 100[/tex]
[tex]I = \dfrac {50000}{0.8}[/tex]
[tex]I = 62500 \;\rm J[/tex]
Hence we can conclude that the input work for the machine is 62500 Joules.
To know more about the efficiency, follow the link given below.
https://brainly.com/question/6672666.
