Question

Write the identity of the missing nucleus for the following nuclear decay reaction: 18 9F→01e+?

Answer 1

Answer:

The missing nucleus $_{8}^{18}\textrm{O}$.

Explanation:

The given nuclear decay reaction is Beta-plus decay.In which a proton gets converted to neutron and an electron neutrino and releases positron particles. This particle carries a charge of +1 units.

$_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e$

$_{9}^{18}\textrm{F}\rightarrow _{8}^{18}\textrm{O}+_{+1}^0e$

The missing nucleus $_{8}^{18}\textrm{O}$.

Answer 2

This element X is an isotope of element O

The core reaction:

$\large{\boxed{\bold{_{9} F ^ {18} ---> _ {8}O^{18} + _ {+1} e ^ 0}}}$

Further explanation

The core reaction is a reaction that causes changes in the core structure.

In the core reaction, the number of atomic numbers and mass numbers of the reactants is the same as the atomic number and mass number of the product

Radioactivity is the process of unstable isotopes towards stable isotopes by decay, by emitting certain particles, among others

• alpha α particles ₂He⁴

• beta β ₋₁e⁰ particles

• gamma particles γ

• positron particles ₁e⁰

Known variable

Core reaction

Asked

Complete the reaction

Answer

The ₉F¹⁸ element is radioactive, so to achieve stability it emits positron ₊₁e⁰ particle which produces a stable ₈X¹⁸ element

Core reactions that occur:

$\large{\boxed{\bold {_ {9} F ^ {18} ---> _ {8} X ^ {18} + _ {+1} e ^ 0}}}$

If we see an atomic number of 8 and we see it in a periodic system, this element X is an element of O

The number of mass O itself can change, it can be worth 16.17, or 18 because element O has an isotope

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Keywords: Core reactions, Radioactivity, isotope