Question

Find the solution for this system of equations.

12x + 15y =34
-6x + 5y =3

x =

y =

Answer 1

Answer:

$x=\frac{5}{6}$

$y=\frac{8}{5}$

Step-by-step explanation:

$12x + 15=34$

$-6x + 5y=3$

In elimination method we try to make the coefficient of one variable same

LEts multiply the second equation by 2

$-6x + 5y=3$ * 2

$-12x + 10y =6$

Now add it with first equation

$12x + 15y=34$

$-12x + 10y =6$

-----------------------------------

       $25y=40$

Divide by 25 on both sides

$y=\frac{8}{5}$

Now plug it in first equation and find out x

$12x + 15y=34$

$12x + 15(\frac{8}{5})=34$

$12x + 24=34$, subtract 24

$12x =10$

Divide by 12 on both sides

$x=\frac{5}{6}$

Answer 2

The value of x is 5/6 and the value of y is 1 3/5.

What are the values of x and y?

12x + 15y =34 equation 1

-6x + 5y =3 equation 2

Multiply equation 2 by 2

-12x + 10y = 6 equation 3

Add equation 3 and equation 1 together

25y = 40

y = 40 / 25

y = 8/5 = 1 3/5

Substitute for y in equation 2

-6x + 5(8/5) =3

-6x + 8 = 3

-6x = -8 + 3

-6x = -5

x = 5/6

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