Graph the function f(x) = (x + 1)(x – 5). Use the drop-down menus to complete the steps needed to graph the function. Identify the x-intercepts: (–1, 0) and (5, 0) Find the midpoint between the intercepts: (2, 0) Find the vertex: Find the y-intercept:

Respuesta :

Answer:

  1. Midpoint of the intercepts is [tex](2,0)[/tex]
  2. Vertex is [tex](2, -9)[/tex]
  3. y intercept is [tex](0,-5)[/tex]

Step-by-step explanation:

Here the function is,

[tex]f(x) = (x + 1)(x-5)[/tex]

The x intercept is the point where the graph intersects the x axis or the point where y or f(x) is 0.

So,

[tex]\Rightarrow f(x) = 0[/tex]

[tex]\Rightarrow (x + 1)(x-5) = 0[/tex]

[tex]\Rightarrow x+1=0, x-5=0[/tex]

[tex]\Rightarrow x=-1, x=5[/tex]

Hence the x-intercepts are [tex](-1,0),(5,0)[/tex]

Their mid point will be,

[tex]=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]

[tex]=(\dfrac{-1+5}{2},\dfrac{0+0}{2})[/tex]

[tex]=(2,0)[/tex]

The general vertex form of quadratic function or parabola is,

[tex]y=a(x-h)^2+k[/tex]

where (h, k) is the vertex.

Here,

[tex]y= (x + 1)(x-5)[/tex]

[tex]=x^2-5x+x-5[/tex]

[tex]=x^2-4x-5[/tex]

[tex]=x^2-2\cdot x\cdot 2-5[/tex]

[tex]=x^2-2\cdot x\cdot 2+2^2-5-2^2[/tex]

[tex]=(x-2)^2-5-4[/tex]

[tex]=(x-2)^2-9[/tex]

[tex]\Rightarrow y=(x-2)^2-9[/tex]

Comparing this to the general form, the vertex is [tex](2, -9)[/tex]

The y intercept is the point where the graph intersects the y axis or the point where x is 0.

Putting x=0 in [tex]f(x) = (x + 1)(x-5)[/tex], we get

[tex]f(0) = (0 + 1)(0-5)=(1)(-5)=-5[/tex]

Therefore, the y intercept is [tex](0,-5)[/tex]


Ver imagen InesWalston

The vertex of the parabola are (2, -9).

The x-intercepts: (–1, 0) and (5, 0).

The midpoints between the intercept are (2, 0).

The y-intercept is (0, -5).

Given

Graph the function f(x) = (x + 1)(x – 5).

What is the general equation of the vertex of a parabola?

The equation of the vertex of the parabola;

[tex]\rm y =a(x-h)^2+k[/tex]

Where h and k are the vertexes of the parabola.

Comparing this to the general form, the vertex is (2, -9).

The x-intercept is the point where the graph intersects the x-axis or the point where y or f(x) is 0.

[tex]\rm f(x) = 0\\\\ f(x)=(x + 1)(x - 5)=0\\\\(x+1)=0, \ x=-1\\\\x-5=0, \ x=5[/tex]

The x-intercepts: (–1, 0) and (5, 0).

The midpoints between the intercept are;

[tex]\rm \dfrac{-1+5}{2}, \ \dfrac{0+0}{2}\\\\\dfrac{4}{2}, 0\\\\2,0[/tex]

The midpoints between the intercept are (2, 0).

The y-intercept is the point where the graph intersects the y axis or the point where x is 0.

f(0) = (0+1). (-5) = 1(-5) = -5

The y intercept is (0, -5).

To know more about Parabola click the link given below.

https://brainly.com/question/8495268

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