Consider the oxidation of sodium metal to sodium oxide described by the balanced equation: 4 na + o2 ? 2 na2o. if 2.55 mol of sodium reacts, what is the percent yield if the reaction actually gives 75.0 g of na2o?
We use the relation of the substances and the amount of sodium to determine the theoretical yield of the reaction. This yield is the amount produced if all the reactant is consumed.
2.55 mol Na (2 mol Na2O / 4 mol Na) ( 61.98 g / 1 mol ) = 79.02 g Na2O
