Respuesta :
Answer:
- 0.665 mol of O₂.
Explanation:
1. Molecular chemical equation:
- 2 KClO₃(s) → 2 KCl(s) + 3 O₂(g)
2. Mole ratios:
- 2 mol KClO₃ : 2 mol KCl : 3 mol O₂
3. Number of moles of KClO₃
- Number of moles = mass in grams / molar mass
- Molar mass of KClO₃ = 122.55 g/mol
- Number of moles of KClO₃ = 54.3 g / 122.5 g/mol ≈ 0.44308 mol
3. Number of moles of O₂
As per the theoretical mole ratio 2 mol of KClO₃ produce 3 mol of O₂, then set up a proportion to determine how many moles of O₂ will be produced from 0.44038 mol of KClO₃.
- 3 mol O₂ / 2 mol KClO₃ = x / 0.44038 mol KClO₃
- x = (3 / 2) × 0.44308 mol O₂ = 0.6646 mol O₂
Round to 3 significant figures: 0.665 mol of O₂ ← answer
0.6645 moles of oxygen O₂ form when 54.3 g solid potassium chlorate KClO₃ completely decomposes
Further explanation
Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
2KClO₃ ⇒ 2KCl + 3O₂
We determine the KClO₃ mole to determine the O₂ mole
M KClO₃ = 1. K + 1. Cl + 3. O
M KClO₃ = 1. 39 + 1. 35.5 + 3. 16
M KClO₃ = 39 + 35.5 + 48
M KClO₃ = 122.5
[tex]\displaystyle mole\:KClO_3=\frac{mass}{molar\:mass}[/tex]
[tex]\displaystyle mole=\frac{54.3}{122.5}=0.443\:mole[/tex]
From the reaction equation, the mole ratio
KClO₃ : O₂ = 2 : 3
then :
[tex]\displaystyle mole\:O_2=\frac{3}{2}\times 0.443\\\\mole\:O_2=\boxed{\bold{0.6645}}[/tex]
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Keywords: mole, oxygen, potassium chlorate, decomposes,potassium chloride