Question

solution 1/3a^2-1/a=1/6a^2
The solution is a=??

Answer 1

Answer:

$a = \frac{1}{6}$

Step-by-step explanation:

Given the equation:

$\frac{1}{3a^2} -\frac{1}{a} =\frac{1}{6a^2}$

then;

$\frac{1-3a}{3a^2} = \frac{1}{6a^2}$

Multiply both sides by $3a^2$ we have;

⇒$1-3a = \frac{1}{2}$

Subtract 1 from both sides we have;

$-3a = -\frac{1}{2}$

Divide both sides by -3 we have;

$a = \frac{1}{6}$

Therefore, the solution is, $a = \frac{1}{6}$

Answer 2

The solution of equation a is 1/6.

Given

Equation; $\rm \dfrac{1}{3a^2}-\dfrac{1}{a}=\dfrac{1}{6a^2}$

How to find the solution to the given equation?

To find the solution of the equation first take LCM to simplify the equation cross multiplication and then simplify.

The solution of the equation is;

$\rm \dfrac{1}{3a^2}-\dfrac{1}{a}=\dfrac{1}{6a^2}\\\\\dfrac{1-3a}{3a^2}= \dfrac{1}{6a^2}\\\\ 6a^2(1-3a)=2 \times 3a^2\\\\6a^2-18a^3=3a^2\\\\Divided \ by \ a^2\\\\6-18a=3\\\\-18a=3-6\\\\-18a=-3\\\\ a = \dfrac{-3}{-18}\\\\a=\dfrac{1}{6}$

Hence, the value of a is 1/6.

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https://brainly.com/question/12895249