Question

For a convex 40-gon, what is the sum of the measures of the interior angles?

Answer 1

The sum of the measures of a polygon's interior angles will always be:  
(n - 2)180° where n is the number of sides/angles.

Plug 40 in for n:
angle sum = (n - 2)180
sum = (40 - 2)180
sum = 38 * 180 = 6840

Thus, the sum of the interior measures of a 40-gon is 6840°.

Answer 2

Sum of the measures of the interior angles is 6,840°

Given that;

Convex of 40-gon

Find:

Sum of the measures of the interior angles

Computation:

Sum of the measures of the interior angles = (n - 2)180

Sum of the measures of the interior angles = [40 - 2]180

Sum of the measures of the interior angles = 6,840°

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