Line L1 has an x-intercept at x = 2 and a y-intercept at y = -10. If L1 is parallel to L2 and L2 has a y-intercept at y = 3, find the x-intercept for line L2.
The slope for L1 is (0- -10)/(2-0) = 5 L2 is parallel to L1 so its slope is also 5. L2 has a y-intercept of 3. Then using y=mx+b, L2 equation is y=5x+3. Then the x-intercept is 0=5x+3, x=-3/5 or -0.6
