Respuesta :

hello here is a solution : 
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Answer:

a = -1

and a ≠ -3 , 3

Step-by-step explanation:

Given Equation :

[tex]\frac{a}{a+3}=\frac{2a}{a-3}-1[/tex]

We need to solve the given equation.

Clearly given equation has 2 rational terms.

We know that Denominator of rational Numbers can not be equal to 0.

So, a + 3 ≠ 0 ⇒ a ≠ - 3    and a - 3 ≠ 0 ⇒ a ≠ + 3

⇒ a can not be equal to 3 and -3.

Now Consider,

[tex]\frac{a}{a+3}=\frac{2a}{a-3}-1[/tex]

[tex]\frac{a}{a+3}=\frac{2a-(a-3)}{a-3}[/tex]

[tex]\frac{a}{a+3}=\frac{2a-a+3}{a-3}[/tex]

[tex]\frac{a}{a+3}=\frac{a+3}{a-3}[/tex]

[tex]a(a-3)=(a+3)(a+3)[/tex]

[tex]a^2-3a=a^2+2(a)(3)+(3)^2[/tex]

[tex]a^2-3a=a^2+6a+9[/tex]

[tex]6a+3a=-9[/tex]

[tex]9a=-9[/tex]

[tex]a=-1[/tex]

Therefore, a = -1

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