Question

v(t)=26,000(0.90^t) find the initial value and the value after 11 years

Answer 1

well you're given the equation and the time.

substitute:

V(t) = 26,000(0.90^t)
V(11) = 26,000(0.90^(11))
V(11) = 8,159.075498
V(11) ≈ 8,159