Question

Which of the following is the area of the special trapezoid if AB = 19, CD = 19, and the height is 14

Answer 1

the answer is 266 units2

Answer 2

Answer:

Area of Trapezoid, having dimension, AB = 19, CD = 19, and the height is 14 is

$=\frac{1}{2}\times [\text{Sum of parallel sides}]\times [\text{Perpendicular distance between them}]\\\\=\frac{1}{2}\times[19+19]\times 14\\\\=\frac{1}{2}\times 38\times 14\\\\ =38 \times 7\\\\=266$

So, Area of trapezoid = 266 cm²