Question

PLEASE HELP ANYONE
Given the information above, find the probability of drawing a blue marble, then a green marble, then a blue marble.

Answer 1

P(1st B) = 1/8
P(2nd G) = 7/7
P(3rd B) = 0/6 = 0 (there is no more blue, so it's impossible)

P(1B AND 1G and 2ndB) = 0/336 

Answer 2

1 blue, 7 green...total of 8 marbles

prob of drawing blue marble : 1/8
without replacing
prob of drawing green marble : 7/7 
without replacing
prob of drawing blue marble : 0/6

probability of all 3 : 1/8 * 7/7 * 0/6 = 0 / 336 = 0%