Question

Find the quotient. (2x4 – 3x3 – 6x2 + 11x + 8) ÷ (x – 2)

Answer 1

The answer is b.) 2x^3+x^2-4x+3+14/x-2

Answer 2

Answer: Quotient will be

$2x^3+x^2-4x+3$

Explanation:

Since we have given that

$f(x)=2x^4-3x^3-6x^2+11x+8$

And

$g(x)=x-2$

We need to divide the f(x) by g(x),

$f(x)=g(x)\times (2x^3+x^2-4x+3)+16$

If we equate the above equation with division algorithm which says,

$a=bq+r\\here,\\\\f(x)=g(x)\times q(x)+r(x)$

so, Quotient will be

$2x^3+x^2-4x+3$