Question

What is the product (6r-1)(-8r-3)

Answer 1

-48r^2-10r+3

is the product

Answer 2

Answer:

$-48r^{2} -10r+3$

Step-by-step explanation:

we have

$(6r-1)(-8r-3)$

Applying distributive property

$(6r-1)(-8r-3)=6r(-8r)+6r(-3)+1(8r)+1(3)\\ \\=-48r^{2} -18r+8r+3\\ \\=-48r^{2} -10r+3$