A student scored 84 and 87 on her first two quizzes.Write and solve a compound inequality to find the possible values for a third quiz score that would give her an average between 85 and 90 inclusive.

Respuesta :

Mean of data = sum of values ÷ number of data

We have three values; 84, 87, and [tex]x[/tex]

Sum of values = [tex]84+87+x[/tex] = [tex]171+x[/tex]

We want the value of [tex]x[/tex] to give mean between 85 and 90 inclusive

[tex]85 \leq \frac{171+x}{3} \leq 90 [/tex]
[tex]85*3 \leq 171+x \leq 90*3[/tex]
[tex]255 \leq 171+x \leq 270[/tex]
[tex]255-171 \leq x \leq 270-171[/tex]
[tex] 84 \leq x \leq 99[/tex]

Hence, the value of [tex]x[/tex] is between 84 and 99 inclusive

Answer:

The score in third quiz must be lie between 84 to 99 inclusive.

Step-by-step explanation:

Let the marks in third quiz be x.

The student scored 84 and 87 on her first two quizzes.

The formula for mean is

[tex]Mean=\frac{\text{Sum of observations}}{\text{No. of observations}}[/tex]

[tex]Mean=\frac{84+87+x}{3}[/tex]

[tex]Mean=\frac{171+x}{3}[/tex]

The average between 85 and 90 inclusive.

[tex]85\leq\frac{171+x}{3}\leq90[/tex]

[tex]85\times 3\leq171+x\leq 90\times 3[/tex]

[tex]255\leq171+x\leq 270[/tex]

[tex]255-171\leq x\leq 270-171[/tex]

[tex]84\leq x\leq 99[/tex]

Since the value of x lies between between 84 to 99 inclusive, therefore the score in third quiz must be lie between 84 to 99 inclusive.

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