Question

A 0.015-kg ball is shot from the plunger of a pinball machine. because of a centripetal force of 0.028 n, the ball fol- lows a circular arc whose radius is 0.25 m. what is the speed of the ball?

Answer 1

Centripetal force is F=mv^2/r.
So v=Sqrt (Fr/m)=(.028•0.25/0.015)^(1/2)=0.683m/s

Answer 2

Answer: The speed of the ball is 0.68 m/s

Explanation:

To calculate the speed of the ball, we use the equation used to calculate centripetal force:

$F=\frac{mv^2}{r}$

where,

F = centripetal force = 0.028 N

v = speed of the ball = ?

m = mass of the ball = 0.015 kg

r = radius of the ball = 0.25 m

Putting values in above equation, we get:

$0.028=\frac{0.015\times (v)^2}{0.25}\\\\v=\sqrt{\frac{0.25\times 0.028}{0.015}}=0.68m/s$

Hence, the speed of the ball is 0.68 m/s