Question

An inequality is shown below:

−np − 3 ≥ 7(c − 4)

Which of the following solves for n?

n ≤ − the quantity 7 times c minus 31 all over p
n ≤ − the quantity 7 times c minus 25 all over p
n ≥ − the quantity 7 times c minus 31 all over p
n ≥ − the quantity 7 times c minus 25 all over p

Answer 1

It should be the second answer.

Reason:
-np-3≥7(c-4)
-np≥7c-28+3
-np≥7c-25
-n≥(7c-25)/p
N≤-(7c-25)/p

Answer 2

Answer: n ≤ − the quantity 7 times c minus 25 all over p

Step-by-step explanation:

Given inequality: $-np-3\geq7(c-4)$

First open parentheses, and solve the right side of the inequality.

$-np-3\geq7c-28$

Add 3 on both sides, we get

$-np\geq7c-25$

Divide -p on both sides (sign will reverse), we get

$n\leq-\frac{7c-25}{p}$

Thus the answer is n ≤ − the quantity 7 times c minus 25 all over p.