Question

what is the total amount of heat required to completely melt 347 grams of ice at t's melting point

Answer 1

The amount of heat required to completely melt 347 g of ice is $\boxed{115.898{\text{kJ}}}$

Further explanation:

Latent heat  

The heat released or absorbed during the process of conversion physical state of a substance without altering the temperature is known as the latent heat.

When the physical state changes from the solid phase to liquid phase then the amount of heat absorbed in this process to completely convert the solid into liquid without altering the temperature is known as the latent heat fusion.

The formula to calculate heat absorbed from latent heat of fusion is,

${\text{q}}={\text{m}}{{\text{H}}_{\text{f}}}$           …… (1)

Here,

q is heat absorbed.

m is mass of substance.

${{\text{H}}_{\text{f}}}$ is latent heat of fusion.

The mass of given ice is 347 g.

The latent heat of fusion of ice is 334 J/g.

Substitute 347 g for m and 334 J/g for ${{\text{H}}_{\text{f}}}$ in equation (1) as follows:

$\align{{\text{q}}&={\text{m}}{{\text{H}}_{\text{f}}}\cr&=\left( {347{\text{ g}}}\right)\left({334{\text{ J/g}}}\right)\cr&=115898{\text{ J}}\cr}$

The heat required to completely melt 347 g of ice is 115898 J.

The heat required in kilojoule is as follows:

$\begin{aligned}q&=(115898\text{ J})\left(\dfrac{1\text{ kJ}}{1000\text{ J}}\right)\\&=115.898\text{ kJ}\end$

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: Latent, Heat, fusion, Latent heat of fusion, temperature, ice, water, vapors, equilibrium, heat required, melting, heat release, heat absorbed, 115.898 kJ.

Answer 2

The amount of heat needed to melt 347 g of ice at it's melting point is 115898 J.

From the question given above, the following data were obtained:

Mass of ice (m) = 347 g

Latent heat of Fusion (L) = 334 J/g

Heat (Q) required =?

The heat required to melt the ice can be obtained illustrated below:

Q = m•L

Q = 347 × 334

Q = 115898 J

Therefore, the amount of heat needed to melt 347 g of ice at it's melting point is 115898 J.

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