Question

A garden supply store sells two types of lawn mowers.Total sales of mowers for the year were $8379.79. The total number of mowers sold was 30. The small mower costs $249.99. The large mower costs $329.99. Find the number of large mowers sold.

Answer 1

value + value = 8379.70
249.99x + 329.99*30-329.99x = 8379.70
-80x + 9899.70 = 8379.70
-80x = -1520.00
x = 19 (number of the cheaper mowers sold)
30-x = 11 (number of more expensive mowers sold)

Answer 2

Answer:

11.

Step-by-step explanation:

Let x be the number of large mowers and y be the number of small mowers.

We have been given that a garden supply store sells two types of lawn mowers. The total number of mowers sold was 30. We can represent this information in an equation as:

$x+y=30...(1)$

We are also told that the large mower costs $329.99. This means cost of x mowers will be 329.99x.

The small mower costs $249.99. This means cost of y mowers will be 249.99y.

Since total sales of mowers for the year were $8379.79. So we can represent this information in an equation as:

$329.99x+249.99y=8379.79...(2)$

We will use substitution method to solve system of equations. From equation (1) we will get,

$y=30-x$

Upon substituting this value in equation (2) we will get,

$329.99x+249.99(30-x)=8379.79$

$329.99x+7499.7-249.99x=8379.79$  

$80x+7499.7=8379.79$      

$80x+7499.7-7499.7=8379.79-7499.7$  

$80x=880.09$    

Let us divide both sides of our equation by 80.

$\frac{80x}{80}=\frac{880.09}{80}$  

$x=11.001125\approx 11$  

Therefore, 11 large mowers were sold.